How do I write a balanced equation for the following...Sulfur trioxide gas is bubbled through 125ml of a 0.165M sodium hydorxide solution?
NaOH + SO3 ==> Na2SO4 + H2O
You balance.
To write a balanced equation for the reaction between sulfur trioxide gas and sodium hydroxide solution, you need to follow a few steps:
Step 1: Write the chemical formula for each reactant and product involved in the reaction.
The chemical formula for sulfur trioxide is SO3, and the formula for sodium hydroxide is NaOH.
Step 2: Determine the reactants and products in the reaction.
Based on the information provided, the reactants are sulfur trioxide (SO3) gas and sodium hydroxide (NaOH) solution. The products of the reaction are not explicitly mentioned, so we need to figure it out.
Step 3: Determine the balanced equation.
To balance the equation, we need to ensure that the same number of atoms of each element is present on both sides of the equation.
The reaction can be represented as follows:
SO3(g) + NaOH(aq) → Na2SO4(aq) + H2O(l)
In this balanced equation, one molecule of SO3 reacts with two molecules of NaOH, producing one molecule of Na2SO4 and one molecule of H2O.
Please note that the coefficients in front of each molecule (e.g., 2NaOH) indicate the number of molecules of that substance involved in the reaction, and they are used to balance the equation. Also, "(aq)" denotes that the substance is in an aqueous solution, and "(l)" denotes a liquid state. Finally, "(g)" indicates a gaseous state.
In summary, the balanced equation for sulfur trioxide gas (SO3) reacting with 125 ml of a 0.165M sodium hydroxide (NaOH) solution would be:
SO3(g) + 2NaOH(aq) → Na2SO4(aq) + H2O(l)