Solve for x:

log base 25 (log base 7 X)= -1/2

log25(log7(x)) = -1/2

since 25^1/2 = 5,
25^-1/2 = 1/5

log7(x) = 1/5
x = 7^1/5

thanks!

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To solve for x in the equation:

log base 25 (log base 7 x) = -1/2

We'll start by applying the logarithmic properties and rules to simplify the equation.

1. Exponentiate both sides with base 25:

25^(log base 25 (log base 7 x)) = 25^(-1/2)

On the left side of the equation, the logarithm and exponent cancel out, leaving us with:

log base 7 x = 1/√25

2. Simplify the right side:

1/√25 can be simplified as 1/5 since the square root of 25 is 5:

log base 7 x = 1/5

3. Convert the logarithmic equation into an exponential equation:

Rewriting the equation in exponential form, we have:

7^(1/5) = x

4. Evaluate the right side:

Using a calculator, we determine that 7^(1/5) is approximately equal to 1.5157.

Therefore, x ≈ 1.5157.

So, the solution for x in the equation log base 25 (log base 7 x) = -1/2 is approximately x = 1.5157.