Ok, so I know I already posted another really long question but we have not learned this yet and are expected to do homework on it. Please help me.
An ideal monotonic gas is compressed at a constant pressure of 0.9 atm from 14 L to 3.5 L.
Note: Atmospheric pressure is 1.013x105 Pa.
By how many cubic meters is the volume reduced?
What is the work done on the gas?
What was the change in the internal energy of the gas?
How much heat was added to the gas during the compression?
To find the change in volume for the gas, you need to subtract the final volume from the initial volume. In this case, the final volume is 3.5 L and the initial volume is 14 L. So, the change in volume is given by:
Change in volume = Final volume - Initial volume
Change in volume = 3.5 L - 14 L
Change in volume = -10.5 L
Therefore, the volume is reduced by 10.5 L.
To find the work done on the gas, you can use the formula:
Work = Pressure x Change in volume
Here, the pressure is given as 0.9 atm. However, it's better to convert it to Pa (Pascal). To convert atm to Pa, use the conversion factor: 1 atm = 1.013x10^5 Pa.
So, the pressure is:
Pressure = 0.9 atm x 1.013x10^5 Pa / 1 atm
Pressure = 91370 Pa
Now, substitute the values into the formula:
Work = 91370 Pa x -10.5 L
Note: 1 L = 0.001 m^3. We convert L to m^3 to get the result in cubic meters.
Work = 91370 Pa x -10.5 L x 0.001 m^3 / 1 L
Work = -959.985 J
Therefore, the work done on the gas is approximately -959.985 J (Joules).
To find the change in internal energy of the gas, you can use the First Law of Thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system (assuming no other forms of energy transfer). In this case, the work done on the gas is negative because the gas is being compressed.
Change in internal energy = Heat added - Work done
Since we're only given the work done (-959.985 J), we need to find the heat added to the gas during the compression. Therefore:
Change in internal energy = Heat added - (-959.985 J)
Change in internal energy = Heat added + 959.985 J
Since we don't have information about the heat added, we cannot determine the change in internal energy for this specific scenario.
Please note that the heat added or removed during the compression is typically not given directly. You might need additional information or equations to calculate it.
I hope this explanation helps you understand how to approach these types of questions. Good luck with your homework!