Some hydrogen occupies 120 ft at 60.0°F. Find the temperature when its volume is 132ft^3 if the pressure remains constant.
To find the temperature when the volume of hydrogen is 132 ft³, we will use Charles's Law, which states that the volume of a gas is directly proportional to its temperature when pressure is constant.
Charles's Law can be represented as:
V₁ / T₁ = V₂ / T₂,
where V₁ and T₁ are the initial volume and temperature, and V₂ and T₂ are the final volume and temperature.
In this case, we have:
V₁ = 120 ft³ (initial volume)
T₁ = 60.0°F (initial temperature)
V₂ = 132 ft³ (final volume)
We need to find T₂ (final temperature).
Rearranging the formula, we have:
T₂ = T₁ * (V₂ / V₁)
Now, let's plug in the values:
T₂ = 60.0°F * (132 ft³ / 120 ft³)
Simplifying the math:
T₂ = 66.0°F
Therefore, when the volume of hydrogen is 132 ft³ and the pressure remains constant, the temperature is 66.0°F.