Determine the mass of calcium hydroxide produced when calcium carbide (CaC2) reacts with 0.64 grams of water according to the following balanced chemical equation:
CaC2 + 2H2O -> Ni(OH)2 + NaNO3
Here is a worked example. Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html
That's about temperature, mine's not. I kind of know the steps but im not getting the right answer, which is 1.32 g Ca(OH)2
Hallie, there is nothing in that post about temperature. It is about how to calculate grams oxygen produced by KClO3 and it gives you a step by step procedure for solving stoichiometry problems. You might have more luck if you had the right equation. I can tell you that
CaC2 + 2H2O does not give you Ni(OH)2 + NaNO3
Also, I don't believe 1.32 g Ca(OH)2 is the correct answer.
To determine the mass of calcium hydroxide (Ca(OH)2) produced, we need to first find the limiting reactant.
1. Calculate the molar mass of calcium carbide (CaC2):
- Calcium (Ca) has a molar mass of 40.08 g/mol
- Carbon (C) has a molar mass of 12.01 g/mol
- Therefore, the molar mass of CaC2 is 40.08 g/mol + 2 * 12.01 g/mol = 64.10 g/mol.
2. Calculate the molar mass of water (H2O):
- Hydrogen (H) has a molar mass of 1.01 g/mol
- Oxygen (O) has a molar mass of 16.00 g/mol
- Therefore, the molar mass of H2O is 2 * 1.01 g/mol + 16.00 g/mol = 18.02 g/mol.
3. Convert the mass of water (0.64 g) to moles:
- Number of moles = mass / molar mass = 0.64 g / 18.02 g/mol ≈ 0.035 moles.
4. Use the balanced chemical equation to determine the stoichiometry:
From the balanced equation, we see that 1 mole of CaC2 reacts with 2 moles of H2O to produce 1 mole of Ca(OH)2.
5. Calculate the mole ratio between water and calcium hydroxide:
- Moles of Ca(OH)2 = 0.035 moles H2O * (1 mole Ca(OH)2 / 2 moles H2O) ≈ 0.018 moles.
6. Calculate the mass of calcium hydroxide produced:
- Mass of Ca(OH)2 = moles of Ca(OH)2 * molar mass of Ca(OH)2 = 0.018 moles * (40.08 g/mol + 2 * 16.00 g/mol) ≈ 1.22 grams.
Therefore, the mass of calcium hydroxide produced when 0.64 grams of water reacts with calcium carbide is approximately 1.22 grams.