What NaCl concentration results when 209 mL of an 0.660 M NaCl solution is mixed with 492 mL of a 0.270 M NaCl solution?

__ mol/.209 L = 0.660 M
__ mol/.492 L = 0.270 M

.. I have no idea how to solve this. I have no idea why I even set up the equation above when it's asking me to solve for molarity and not mols.. Do i just add 0.660 + 0.270 together since it's mixed together? Can it be that simple? Please help!

thanks Dr. Bob!

Ah, chemistry can be quite salty sometimes, can't it? Don't worry, I'm here to lighten the mood and help you with your question!

To find the final concentration of the NaCl solution when the two solutions are mixed, you need to consider the total amount of NaCl and the total volume of the solution.

First, let's calculate the total amount of NaCl:

0.660 M x 0.209 L = 0.13794 mol NaCl (for the first solution)
0.270 M x 0.492 L = 0.13284 mol NaCl (for the second solution)

Now, let's add these two amounts together:

0.13794 mol + 0.13284 mol = 0.27078 mol NaCl

Next, let's calculate the total volume of the solution:

0.209 L + 0.492 L = 0.701 L

Lastly, divide the total amount of NaCl by the total volume of the solution to find the final concentration:

0.27078 mol NaCl / 0.701 L = 0.387 M NaCl

So, the final concentration of the NaCl solution when the two solutions are mixed is 0.387 M. Voila!

To find the final NaCl concentration, you need to use the concept of concentration and the principle of conservation of mass.

First, you need to convert the given volumes of solutions into liters:
209 mL = 0.209 L
492 mL = 0.492 L

Now let's determine the amount of NaCl in each solution:

For the 0.660 M NaCl solution:
Amount of NaCl = concentration × volume
Amount of NaCl = 0.660 M × 0.209 L

For the 0.270 M NaCl solution:
Amount of NaCl = concentration × volume
Amount of NaCl = 0.270 M × 0.492 L

Now, add up the amounts of NaCl from both solutions to find the total amount of NaCl in the final solution:

Total amount of NaCl = Amount from first solution + Amount from second solution

Finally, divide the total amount of NaCl by the total volume of the final solution to find the final NaCl concentration:

Final NaCl concentration = Total amount of NaCl / Total volume of the final solution

By following these steps, you should be able to calculate the final NaCl concentration.

No, you can't add molarities but you can add mols. mols = M x L =

mols soln 1 = 0.209 x 0.660 = ?
mols soln 2 = 0.492 x 0.270 = ?
Total mols = mols soln 1 + mols soln 2.
Total volume = L soln 1 + L soln 2.
Then M NaCl = total mols/total L.