Find the volume of a rectangular prism whose dimensions are twice those of another rectangular prism that has a volume of 120 cm3
if linear dimension grows by a factor of n
area grows by n^2
volume grows by n^3
so, 2x the dimension yields 8x the volume.
A rectaungular prism has a volume of 360 inches cubed. What base measurements could the prism have?
quiz s and tests dont have any answers which make people fail :/
To find the volume of the larger rectangular prism, we need to know the dimensions of the smaller prism. The relationship between the dimensions of the two prisms is that the larger prism's dimensions are twice as large as the smaller prism's dimensions.
Let's assume that the dimensions of the smaller prism are length (L), width (W), and height (H).
Given that the volume of the smaller prism is 120 cm^3, we can use the formula for volume: V = L * W * H.
If the dimensions of the larger prism are twice those of the smaller prism, then the dimensions of the larger prism are 2L, 2W, and 2H.
The volume of the larger prism (V') can be calculated using the same formula: V' = (2L) * (2W) * (2H) = 8 * (L * W * H).
Since we know that the volume of the smaller prism is 120 cm^3, we can substitute that value into the equation:
V' = 8 * (120) = 960 cm^3.
Therefore, the volume of the larger rectangular prism is 960 cm^3.