I am supposed to write a quadratic equation in the varible x having the given numbers as solutions. Type the equation in standard ax^2+bx+c=0 my solution is 1, only one solution.
The equation is __________=0?
Try X^2 -2X +1.
Factored this gives
(X-1)(X-1) = 0
and X = 1 and 1.
Thank you, I will.
To write a quadratic equation with the given number as a solution, you need to ensure that there's only one solution. In other words, you want to create an equation where the discriminant (the expression under the square root in the quadratic formula) is zero.
The quadratic formula is given by:
x = (-b ± √(b² - 4ac)) / (2a)
When the discriminant is zero, it means that the expression under the square root is equal to zero, so:
b² - 4ac = 0
Since you want only one solution, you know that one of the solutions will be the given number, which in this case is 1. To find the equation, you can substitute these values into the equation:
b² - 4ac = 0
(1)² - 4a(1)(c) = 0
1 - 4ac = 0
The equation becomes:
1 - 4ac = 0
So, the quadratic equation is:
1 - 4ac = 0