Cu2S + O2- 2Cu +SO2
when 10.2 mol Cu2S react with oxygen, how many moles of Cu are formed?
path?
Look at the equation. The coefficients are not there because they look pretty.
1 mol Cu2S yields 2 mols Cu;
2 mol Cu2S yields 4 mols Cu;
5 mol Cu2S yields 10 mols Cu;
10 mol Cu2S yields 20 mols Cu.
Get the picture?
So 10.2 mol Cu2S yields ...... mols Cu.
so it is 20.4 mols cu???
The balanced chemical equation for the reaction is:
Cu2S + O2 -> 2Cu + SO2
According to the equation, 1 mole of Cu2S produces 2 moles of Cu.
To find out how many moles of Cu are formed when 10.2 moles of Cu2S react, we can use a ratio:
10.2 mol Cu2S x (2 mol Cu / 1 mol Cu2S) = 20.4 mol Cu
So, when 10.2 moles of Cu2S react, 20.4 moles of Cu are formed.
To determine how many moles of Cu are formed when 10.2 mol of Cu2S reacts with oxygen, we first need to identify the balanced chemical equation. The given equation is:
Cu2S + O2 → 2Cu + SO2
According to the balanced equation, 1 mol of Cu2S reacts with 1 mol of O2 to produce 2 mol of Cu.
Now, we can set up a proportion to calculate the number of moles of Cu:
(10.2 mol Cu2S / 1) × (2 mol Cu / 1 mol Cu2S) = 20.4 mol Cu
Therefore, when 10.2 mol of Cu2S reacts with oxygen, 20.4 mol of Cu are formed.
Path:
1. Identify the balanced chemical equation.
2. Determine the stoichiometric ratio between Cu2S and Cu from the balanced equation.
3. Set up a proportion to calculate the number of moles of Cu using the given 10.2 mol of Cu2S.