Cu2S + O2- 2Cu +SO2
when 10.2 mol Cu2S react with oxygen, how many moles of Cu are formed?
path?
See your post above.
To find out how many moles of Cu are formed when 10.2 mol Cu2S react with oxygen, we need to use the balanced equation:
Cu2S + O2 → 2Cu + SO2
From the equation, we can see that 1 mole of Cu2S reacts to produce 2 moles of Cu. Therefore, we first need to calculate the number of moles of Cu2S present:
10.2 mol Cu2S × (2 mol Cu / 1 mol Cu2S) = 20.4 mol Cu
Now we can determine the number of moles of Cu formed by multiplying the number of moles of Cu2S by the stoichiometric coefficient of Cu in the balanced equation:
20.4 mol Cu × (2 mol Cu / 1 mol Cu2S) = 40.8 mol Cu
Therefore, when 10.2 mol of Cu2S reacts with oxygen, 40.8 mol of Cu are formed.