Physics. PLEASE HELP!!

A small car of mass 985 kg is parked behind a small truck of mass 1551 kg on a level road. The brakes of both the car and the truck are off so that they are free to roll with negligible
friction. A 83 kg woman sitting on the tailgate of the truck shoves the car away by exerting a constant force on the car with her feet. The car accelerates at 0.3 m/s2. What is the acceleration of the truck?
Answer in units of m/s2

  1. 👍
  2. 👎
  3. 👁
  1. The mass of the car, m = 985 kg, acceleration of the car, a = 0.3 m/s^2
    According to Newton's 2nd law, force exerted on the car,
    F = ma = 985 x 0.3 = 295.5 N
    According to Newton's 3rd law, the same force in the opposite direction will be exerted on the truck.

    Mass of the truck with the woman, M = 1551 + 83 = 1634 kg
    Force acting on the truck, F = 1634 N [ same as the force on the car ]
    F = M•a1 or, a1 = F/M = 295.5/1634 = 0.18 m/s^2
    So the acceleration of the truck will be 0.18 m/s^2 and it's direction will be opposite of the car's acceleration.

    1. 👍
    2. 👎

Respond to this Question

First Name

Your Response

Similar Questions

  1. SCIENCE

    Two objects with equal masses are in motion. Which object will have more kinetic energy? (1 point) the object with the greater volume the object with the greater velocity the object with the greater density the object with the

  2. Science

    Kinetic energy is transferred from a bowling ball to a bowling pin, causing the pin to fly away at a much higher speed than the bowling ball. What does this tell you about the bowling pin?(1 point) The pin has much less kinetic

  3. Physics Help

    A small, 200 g cart is moving at 1.50 m/s on an air track when it collides with a larger, 2.00 kg cart at rest. After the collision, the small cart recoils at 0.890 m/s. Q: What is the speed of the large cart after the collision?

  4. Physics

    A small car (mass 380 ) is pushing a large truck (mass 1000 ) due east on a level road. The car exerts a horizontal force of 1580 on the truck. What is the magnitude of the force that the truck exerts on the car?

  1. Science

    A large truck and a small car are found to have the same kinetic energy. How is this possible? The Answer is The car must be moving with a greater velocity. Please correct me if i'm wrong

  2. Physics

    A 1500 kg car traveling at 17.6 m/s to the south collides with a 5000 kg truck that is initially at rest at a stoplight. The car and truck stick together and move together after the collision. What is the final velocity of the

  3. Physics

    A tow truck pulls a car from rest onto a level road. The tow truck exerts a horizontal force of 1500 N on the car. The frictional force on the car is 810 N. Calculate the work done by each of the following forces on the car as the

  4. Physics

    A car of mass m moving at a speed v1 collides and couples with the back of a truck of mass 3m moving initially in the same direction as the car at a lower speed v2. (Use any variable or symbol stated above as necessary.) (b) What

  1. Physics

    Car A with mass of 1250 kg is traveling at 30 m/s to the east. Car B is a truck with mass of 2000 kg, traveling to the west at 25 m/s. Assume these two vehicles experience an inelastic collision but do not stick together and car a

  2. physics

    true or false If a net force acts on an object, the object's speed will change. An object's velocity will change if a net force acts on the object. If two object have the same acceleration, they are under the influence of equal

  3. Physics

    Consider the collisions between a car and a truck whose weight is much heavier than the car (M ≫ m). Friction is so small that it can be ignored. If they are both moving at the same speed when they collide, what best describes

  4. Physics

    The diagram below shows a large cube of mass 25 kg being accelerated across a frictionless level floor by a horizontal force, F. A small cube of mass 4.0 kg is in contact with the front surface of the cube. The coefficient of

You can view more similar questions or ask a new question.