Calculate the concentration of aqueous solution of barium hydroxide whose pH is 12
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To calculate the concentration of a solution of barium hydroxide (Ba(OH)2) with a given pH, we need to understand how pH and pOH are related.
1. First, calculate the pOH using the formula: pOH = 14 - pH
In this case, pOH = 14 - 12 = 2
2. The pOH is related to the concentration of the hydroxide ion (OH-) in the solution. The hydroxide ion concentration can be determined using the equation: [OH-] = 10^(-pOH)
In our case, [OH-] = 10^(-2) = 0.01 M (0.01 mol/L)
3. Barium hydroxide (Ba(OH)2) dissociates in water to release two hydroxide ions for every one molecule of Ba(OH)2. This means the concentration of barium hydroxide is twice the concentration of hydroxide ions.
Therefore, the concentration of barium hydroxide is 2 * [OH-] = 2 * 0.01 M = 0.02 M (0.02 mol/L)
Hence, the concentration of the aqueous solution of barium hydroxide with a pH of 12 is 0.02 M.