At what depth in water is the pressure equal to 2.0m atmosphere?
from wikipedia:
The density of water also causes problems that increase dramatically with depth. The atmospheric pressure at the surface is 14.7 pounds per square inch or around 100 kPa. A comparable water pressure occurs at a depth of only 10 m (33 ft) (9.8 m (32 ft) for sea water). Thus, at about 10 m below the surface, the water exerts twice the pressure (2 atmospheres or 200 kPa) on the body as air at surface level.
I still don't gt u would you kindly elabora fathor...thanks though
The pressure in water increases with depth due to the weight of the water above it. The relationship between depth and pressure in a fluid is given by the equation:
Pressure = Density × Gravity × Depth
Where:
- Pressure is the applied force per unit area measured in Pascals (Pa).
- Density is the density of the fluid, which for freshwater is approximately 1000 kg/m^3.
- Gravity is the acceleration due to gravity, which is approximately 9.8 m/s^2.
- Depth is the distance from the surface of the water measured in meters (m).
To find the depth at which the pressure is equal to 2.0 atmospheres, we can rearrange the equation:
Pressure = Density × Gravity × Depth
2.0 atm = 1000 kg/m^3 × 9.8 m/s^2 × Depth
Converting 2.0 atmospheres to Pascals, we get:
2.0 atm = 2.0 × 101 325 Pa = 202 650 Pa
Now we can solve for the depth:
202 650 Pa = 1000 kg/m^3 × 9.8 m/s^2 × Depth
Dividing both sides by (1000 kg/m^3 × 9.8 m/s^2), we get:
Depth = 202 650 Pa / (1000 kg/m^3 × 9.8 m/s^2)
Depth ≈ 20.66 m
Therefore, at a depth of approximately 20.66 meters in water, the pressure would be equal to 2.0 atmospheres.
To determine at what depth in water the pressure is equal to 2.0 atmospheres (atm), we can use the concept of hydrostatic pressure. The hydrostatic pressure is given by the equation:
P = ρgh
Where:
P = pressure
ρ = density of the fluid
g = acceleration due to gravity
h = height or depth
The density of water is approximately 1000 kg/m³, and the standard acceleration due to gravity is approximately 9.8 m/s².
Let's substitute these values into the equation and solve for the depth (h).
2.0 atm = (1000 kg/m³)(9.8 m/s²)h
First, let's convert the pressure from atmospheres to pascals (Pa). One atmosphere is equal to 101,325 Pa.
2.0 atm = 2.0 x 101,325 Pa = 202,650 Pa
Now, we can rearrange the equation to solve for h:
h = (2.0 atm / (1000 kg/m³ x 9.8 m/s²))
h = (202,650 Pa / (1000 kg/m³ x 9.8 m/s²))
h ≈ 20.65 meters
Therefore, at approximately 20.65 meters depth in water, the pressure will be equal to 2.0 atmospheres.