The primary voltage is still 120 V and the number of primary turns = 60, but now the power in the primary side is 3000 Watts and there is a 120 ohm resistor connected to the secondary. Find the current in the resistor, and the secondary voltage and # turns.
V=d+t
120m =d+60m
120m _60m =t
60=t
To find the current in the resistor, we can use Ohm's Law, which states that current (I) is equal to the voltage (V) divided by the resistance (R). In this case, the resistance (R) is given as 120 ohms.
We can find the current using the formula:
I = V / R
Substituting the values, we have:
I = 120 V / 120 ohms
I = 1 Ampere (A)
Therefore, the current in the resistor is 1 Ampere (A).
To find the secondary voltage (Vsecondary) and the number of turns in the secondary coil (# turns), we can use the power formula:
P = IV
where P is the power and I is the current.
We know the power in the primary side (Pprimary) is 3000 Watts and the primary voltage (Vprimary) is 120 V. Assuming no losses, we can say that power in the primary side is equal to the power in the secondary side:
Pprimary = Psecondary
Substituting the values, we have:
3000 Watts = Vsecondary * I
Since we have already found the current (I) to be 1 Ampere (A), we can rearrange the formula to solve for Vsecondary:
Vsecondary = Pprimary / I
Vsecondary = 3000 Watts / 1 A
Vsecondary = 3000 V
Therefore, the secondary voltage is 3000 Volts (V).
To find the number of turns in the secondary coil (# turns), we can use the transformer equation:
Vprimary / Vsecondary = Nprimary / Nsecondary
where Nprimary and Nsecondary represent the number of turns in the primary and secondary coils, respectively.
Substituting the values, we have:
120 V / 3000 V = 60 turns / Nsecondary
Cross-multiplying and solving for Nsecondary, we get:
Nsecondary = (60 turns * 3000 V) / 120 V
Nsecondary = 1500 turns
Therefore, the number of turns in the secondary coil is 1500 turns.