To what volume must 481 mL of 12 M

Ca(OH)2 solution be diluted to make a 2 M Ca(OH)2 solution?
a)1.352L
b)2.886L
c)2.10833L
d)none of the above

c1v1 = c2v2

c = concn
v = volume

2.886L

To find the volume to which a solution must be diluted, we can use the equation:

C1V1 = C2V2

Where:
C1 = initial concentration of the solution (in this case, 12 M)
V1 = initial volume of the solution (in this case, 481 mL)
C2 = final concentration of the solution (in this case, 2 M)
V2 = final volume of the solution (what we need to find)

Rearranging the equation to solve for V2, we have:

V2 = (C1V1) / C2

Substituting the given values, we have:

V2 = (12 M * 481 mL) / 2 M

V2 = (12 * 481) / 2

V2 = 4,812 / 2

V2 = 2,406 mL

Therefore, 481 mL of 12 M Ca(OH)2 solution must be diluted to 2,406 mL or 2.406 L to make a 2 M Ca(OH)2 solution.

None of the given options (a, b, c) match this result.