Chemistry

when 0.20 mole HF is dissolved in water to a volume of 1.00 L, 5.8% of the HF dissociates to form F- (aq). What is the equilibrium constant for the reaction ?

HF(aq) + H2O (I) ----- F- (aq)+H3O+(aq)

asked by Elmali
  1. 0.2mol/L -= 0.2M
    0.20 x 0.00.058 = 0.0116
    ..........HF ==> H^+ + F^-
    initial...0.2.....0.....0
    change.-0.0116...0.0116..0.0116
    equil.....?........?......?

    Ka = (H^+)(F^-)/(HF)
    Substitute from the ICE chart above and solve for Ka.

    posted by DrBob222
  2. ho

    posted by Anonymous
  3. Answer is 7.14x10^-4

    posted by Bubblesss

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