The sum of two numbers is fifty-two. Their difference is twenty-two. What are the numbers?
37 and 15
what is the solution set of the equation?round to the nearst hundreth if neccessary 3y+4y-2=0
4Y + 3Y -2=0 SO THE ANS IS 2/7 =0.285... TO THE NEAREST HUNDREDTH IS 0.29
To find the two numbers, we can set up a system of equations based on the given information.
Let's assume the first number is x and the second number is y.
We are given two pieces of information:
1. The sum of the two numbers is fifty-two: x + y = 52
2. The difference between the two numbers is twenty-two: x - y = 22
Now, we can solve this system of equations using either substitution or elimination method.
Let's use the elimination method:
Adding both equations, we eliminate the variable y:
(x + y) + (x - y) = 52 + 22
Simplifying the equation:
2x = 74
Dividing by 2 on both sides:
x = 37
Now, substitute the value of x into one of the original equations, let's use equation (1):
x + y = 52
Substituting x = 37:
37 + y = 52
Subtracting 37 from both sides:
y = 15
Therefore, the two numbers are 37 and 15.