Find the solution of the given system by the method of addition that was used in Examples 4 and 5. If there is no solution or infinitely many solutions, state so. Put the value for x in the blank.
2x - 3y = 1; x + 2y = 4
I think you are describing the method of elimination
1st equation -----> 2x-3y = 1
2nd times 2 -----> 2x + 4y = 8
subtract them
-7y = -7
y = 1
back into the 2nd:
x + 2 = 4
x = 2
x = 2, y = 1