There are 3.29g of Iodine 126 remaining in a smaple originally containing 26.3 g of iodine 126 the half life of iodine 126 is 13 days. How old is the sample?
k = 0.693/t1/2.
Then ln(No/N) = kt
No = 26.3
N = 3.29
k from above.
solve for t.
Post your work if you get stuck.
To determine the age of the sample, we need to use the concept of half-life. The half-life of iodine-126 is given as 13 days.
First, we need to find out how many half-lives have passed to reach the remaining amount of iodine-126. We can do this by dividing the initial amount of iodine-126 (26.3g) by the amount remaining (3.29g).
Number of half-lives = (initial amount / remaining amount)
Number of half-lives = (26.3g / 3.29g)
Number of half-lives ≈ 7.98
Since we cannot have a fraction of a half-life, we can round this number up to 8. It means that 8 half-lives have passed.
Next, we need to calculate the time it takes for 8 half-lives. Since the half-life of iodine-126 is given as 13 days, we can multiply the half-life by the number of half-lives:
Total time = (half-life) x (number of half-lives)
Total time = 13 days x 8
Total time = 104 days
Therefore, the sample is approximately 104 days old.