How many moles of calcium chloride hexahydrate will be produced from 4.00 mol calcium carbonate?
CaCO3 ==> CaCl2.6H2O
1 mol CaCO3 will produce 1 mol CaCl2.6H2O so 4.0 mols CaCO3 will produce......
To determine how many moles of calcium chloride hexahydrate will be produced from 4.00 mol of calcium carbonate, we need to use the stoichiometry of the balanced chemical equation.
First, let's write the balanced chemical equation for the reaction. Calcium carbonate (CaCO3) reacts with hydrochloric acid (HCl) to form calcium chloride hexahydrate (CaCl2·6H2O), carbon dioxide (CO2), and water (H2O).
The balanced chemical equation is:
CaCO3 + 2HCl → CaCl2·6H2O + CO2 + H2O
From the balanced equation, we can see that 1 mol of calcium carbonate reacts with 2 mol of hydrochloric acid to produce 1 mol of calcium chloride hexahydrate.
Therefore, using the stoichiometry of the balanced equation:
4.00 mol CaCO3 x (1 mol CaCl2·6H2O / 1 mol CaCO3) = 4.00 mol CaCl2·6H2O
Hence, 4.00 moles of calcium carbonate will produce 4.00 moles of calcium chloride hexahydrate.
To determine the number of moles of calcium chloride hexahydrate produced from 4.00 mol of calcium carbonate, you need to consider the balanced equation for the reaction between calcium carbonate and hydrochloric acid:
CaCO3 + 2HCl -> CaCl2 + CO2 + H2O
From the balanced equation, you can see that 1 mol of calcium carbonate reacts to produce 1 mol of calcium chloride. Therefore, the number of moles of calcium chloride hexahydrate will be equal to the number of moles of calcium carbonate used.
Given that you have 4.00 mol of calcium carbonate, the number of moles of calcium chloride hexahydrate produced will also be 4.00 mol.