A solution was prepared by dissolving 0.817g of sulfur S8, in 100.0g of acetic acid, HC2H3O2. Calculate the freezing point and boiling point of the solution

Question

A solution was prepared by dissolving 0.817g of sulfur S8, in 100.0g of acetic acid, HC2H3O2. Calculate the freezing point and boiling point of the solution

Answer 1

convert g S to mols.

(mols S/kg solvent) = molality
delta T = K_f*molality
delta T = K_b*molality

I presume you have the constants for boiling point and freezing point for acetic acid.

Answer 2

To calculate the freezing and boiling points of a solution, we need to know the molality of the solution and the molal freezing point depression and boiling point elevation constants.

Let's start by calculating the molality of the solution:

Molality (m) = moles of solute / mass of solvent (in kg)

First, we need to calculate the number of moles of sulfur (S8) in 0.817g:

Number of moles = mass / molar mass
Molar mass of S8 = 8 * atomic mass of sulfur
Assuming atomic mass of sulfur is approximately 32 g/mol:
Molar mass of S8 = 8 * 32 g/mol = 256 g/mol

Number of moles of S8 = 0.817g / 256 g/mol

Next, we need to calculate the mass of acetic acid (HC2H3O2) in the solution:

Mass of acetic acid = 100.0g

Now, we can calculate the molality of the solution:

Molality (m) = moles of sulfur / mass of acetic acid (in kg)

Convert the mass of solvent to kg:
Mass of acetic acid (in kg) = 100.0g / 1000g/kg

Finally, substitute the values into the equation and calculate the molality:

Molality (m) = moles of sulfur / (mass of acetic acid (in kg))
= (0.817g / 256 g/mol) / (100.0g / 1000g/kg)

Now that we have the molality of the solution, we need to determine the freezing point and boiling point constants for acetic acid.

The molal freezing point depression constant (Kf) for acetic acid is approximately 3.90 °C/m, and the molal boiling point elevation constant (Kb) for acetic acid is approximately 3.07 °C/m.

We can now calculate the freezing point depression and boiling point elevation using the following formulas:

Freezing point depression (ΔTf) = Kf * molality
Boiling point elevation (ΔTb) = Kb * molality

Substituting the values, we can calculate the freezing and boiling points:

Freezing point = freezing point of acetic acid - ΔTf
Boiling point = boiling point of acetic acid + ΔTb

The freezing point and boiling point of acetic acid are approximately 16.6 °C and 118.1 °C, respectively.

Substitute the values into the formulas to calculate the freezing and boiling points.

Therefore, the freezing point and boiling point of the solution can be calculated based on the provided information.

A solution was prepared by dissolving 0.817g of sulfur S8, in 100.0g of acetic acid, HC2H3O2. Calculate the freezing point and boiling point of the solution

convert g S to mols.

Conteh

To calculate the freezing and boiling points of a solution, we need to know the molality of the solution and the molal freezing point depression and boiling point elevation constants.