A certain type of combination lock has
3 dials: the first 2 dials each have settings for all the digits 0 through 9 and the third has settings for all the 26 capital letters of the alphabet. A combination consists of one setting from each of the dials. How many different combinations are possible?
Yep, thats wrong. THe real method is 10*26, since for every number there is 26 letters, so 26*10=260
I believe its 10*10*26.
in the first spot, you can choose from the numbers 0-9.
In the second spot (since they don't say you can't repeat, we have to assume that you can repeat digits) you can also choose between 0-9
In the final spot, you can pick from any of the 26 letters of the alphabet.
To find the number of different combinations possible, we need to calculate the product of the number of settings on each dial.
The first dial has 10 settings (digits 0-9).
The second dial also has 10 settings (digits 0-9).
The third dial has 26 settings (capital letters A-Z).
To find the total number of combinations, we multiply the number of settings on each dial:
Number of combinations = (number of settings on 1st dial) * (number of settings on 2nd dial) * (number of settings on 3rd dial)
Number of combinations = 10 * 10 * 26
Number of combinations = 2600
Therefore, there are 2600 different combinations possible with this type of combination lock.
9*9*26
does not look right.
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