A jetliner has a velocity of 95 m/s. What is the displacement of the jetliner at t=3.0 seconds

X = V t = 95 t,

if it started at X = 0 at t = 0.

So, multiply 95 by 3.

285. I answered the question correctly on a Topic Test Review on my E2020 physics class. :D hope it helps!

To find the displacement of the jetliner at t=3.0 seconds, we need to know the initial position of the jetliner. If we assume that the initial position is 0 (meaning the jetliner starts at the origin), we can calculate the displacement.

Displacement (d) can be calculated using the formula:

d = v * t

Where:
d = displacement
v = velocity
t = time

Given:
v = 95 m/s
t = 3.0 seconds

Plugging in the values, we can calculate the displacement:

d = 95 m/s * 3.0 seconds
d = 285 meters

Therefore, the displacement of the jetliner at t=3.0 seconds is 285 meters.

To find the displacement of the jetliner at t=3.0 seconds, you will need to know the direction of the jetliner's motion as well. Displacement is a vector quantity that includes both magnitude (the distance) and direction.

If you have both the magnitude and direction of the velocity, you can determine the displacement. However, if only the magnitude of the velocity is given, we can assume that the direction is in a straight line.

Assuming the jetliner's velocity remains constant over time, you can use the equation:

Displacement = Velocity × Time

Displacement = 95 m/s × 3.0 s

Displacement = 285 m

Therefore, the displacement of the jetliner at t=3.0 seconds is 285 meters.