left a line out of answer

1.546x10-2mols CuSO4x2=3.09x10-2 mole ions

To determine the missing information, let's first break down the given equation:

1.546x10^-2 mol CuSO4 x 2 = 3.09x10^-2 mole ions

We know that 1 mole of CuSO4 contains 2 moles of ions (Copper ion and Sulfate ion). Here, the equation is using stoichiometry to convert the number of moles of the compound (CuSO4) to the number of moles of ions.

To find the missing line or information, we need to determine the ionization that occurs in the CuSO4 compound. The chemical formula for copper sulfate (CuSO4) indicates that it dissociates into copper ions (Cu^2+) and sulfate ions (SO4^2-). Each copper sulfate (CuSO4) unit generates one copper ion (Cu^2+) and one sulfate ion (SO4^2-) when it dissolves.

Therefore, 1 mole of CuSO4 will yield:

- 1 mole of Cu^2+ ions
- 1 mole of SO4^2- ions

Hence, the missing line that should be added to the equation is:

1.546x10^-2 mol CuSO4 x 2 = 3.09x10^-2 mole ions
(1.546x10^-2 mol CuSO4 x 1) = (3.09x10^-2 mol Cu^2+) + (3.09x10^-2 mol SO4^2-)