y=sin(2pi*x-pi)

find the amplitude, period, and phase shift

write it as

y = sin 2π(x - 1/2)

after having done several for you, you should be able to follow the procedure I showed you.
Let me know what you get.

To find the amplitude, period, and phase shift of the function y = sin(2πx - π), we can use the standard equation of a sine function: y = A*sin(Bx - C) + D, where A is the amplitude, B determines the period, C indicates the phase shift, and D represents the vertical shift (if any).

Amplitude: The amplitude, denoted by A, is the maximum value the function reaches from its midline. In this case, since there is no vertical shift (D = 0), the amplitude is simply the coefficient of sin, which is 1. Therefore, the amplitude is 1.

Period: The period of a sine function is the distance it takes to complete one full cycle. It can be determined using the formula T = 2π/B, where T represents the period and B is the coefficient of x. In this case, the coefficient of x is 2π, so the period is T = 2π/(2π) = 1. Therefore, the period is 1.

Phase Shift: The phase shift, denoted by C, refers to how much the function is shifted horizontally. It can be calculated using the formula C = (C/B), where C represents the phase shift and B is the coefficient of x. In this case, the coefficient of x is 2π, and the C term in the function is -π. Therefore, the phase shift is C = (-π)/(2π) = -1/2. Thus, the function is shifted to the right by 1/2 units.

To summarize:
Amplitude = 1
Period = 1
Phase Shift = -1/2