Sulfuric acid (H2SO4) is a very strong diprotic acid. If 0.054 moles of sulfuric acid is mixed with water to make 667 milliliter of solution,what is the molarity of H+?

Answer in units of M

doing mole/liter doesn't work

Sure it does. But you must calculate and give what the problem asks you to calculate.

mols H2SO4 = 0.054/0.667 L = ?
mols H^+ = twice that.

To find the molarity of H+ in the sulfuric acid solution, we need to first understand that sulfuric acid (H2SO4) is a diprotic acid. This means that each molecule of sulfuric acid can donate two hydrogen ions (H+).

Given that we have 0.054 moles of sulfuric acid and the solution volume is 667 milliliters, we can start by converting this volume to liters:

0.667 L = 0.667 liters

Next, we need to determine the number of moles of H+ ions present in the solution. Since each molecule of sulfuric acid donates two H+ ions, we can multiply the number of moles of sulfuric acid by 2:

0.054 moles × 2 = 0.108 moles of H+ ions

Finally, to find the molarity (M) of H+ ions, we divide the moles of H+ ions by the volume of the solution in liters:

Molarity (M) = moles of solute / volume of solution in liters

Molarity (H+) = 0.108 moles / 0.667 liters

Simplifying further:

Molarity (H+) ≈ 0.162 M

Therefore, the molarity of H+ ions in the given sulfuric acid solution is approximately 0.162 M.

To determine the molarity of H+ in the solution, we need to consider that sulfuric acid (H2SO4) is a diprotic acid, meaning it can donate two protons (H+ ions) per molecule.

Given:
Moles of sulfuric acid (H2SO4) = 0.054 moles
Volume of solution = 667 milliliters = 0.667 liters

First, we need to calculate the number of moles of H+ ions present in the solution. Since each sulfuric acid molecule donates two protons, the number of moles of H+ ions will be twice the number of moles of sulfuric acid.

Moles of H+ ions = 2 x Moles of sulfuric acid
Moles of H+ ions = 2 x 0.054 moles

Now, we can calculate the molarity (M) of H+ ions using the following formula:

Molarity (M) = Moles of solute / Volume of solution in liters

Molarity of H+ ions = (2 x 0.054 moles) / 0.667 liters

Calculating this expression will give us the molarity of H+ in the solution.