Is this how I right this formula for dichlorodiaquoplatinum (II)
(PtCl2(H2O)2)
I think brackets instead of parentheses.
[Pt(H2O)2Cl2]
Yes, that is the correct way to write the formula for dichlorodiaquoplatinum(II), also known as [PtCl2(H2O)2].
To correctly write the formula for dichlorodiaquoplatinum (II), we need to understand the structure and composition of the compound.
This compound consists of a platinum (Pt) atom bonded with two chloride (Cl) ions and two water (H2O) molecules.
To write the formula, we can start by representing the platinum atom, which is the central atom in this compound. Since it is a cation with a +2 charge, we use the symbol "Pt" followed by a Roman numeral in parentheses, indicating the charge: Pt(II).
Next, we add the ligands bonded to the platinum atom. Ligands are molecules or ions that surround the central metal atom. In this case, we have two chloride ions (Cl-) and two water molecules (H2O).
To represent the chloride ions, we write the symbol "Cl" and add the subscript "2" to indicate there are two chloride ions bonded to platinum: Cl2.
For the water molecules, we write the symbol "H2O" and add the subscript "2" to indicate that there are also two water molecules bonded to platinum: (H2O)2.
Combining all the components, we can write the formula for dichlorodiaquoplatinum (II) as:
Pt(II)Cl2(H2O)2