How many moles of O are there in 32.4g N2O5, how many oxygen and nitrogen atoms are there in the 32.4g?
Answered above by Damon.
To find the number of moles of oxygen (O) in a given mass of N2O5, we need to use the molar mass of N2O5 and the concept of molar ratios.
Step 1: Determine the molar mass of N2O5:
The molar mass is the sum of the atomic masses in a molecule.
Molar mass of N2O5 = (2 * atomic mass of N) + (5 * atomic mass of O)
The atomic mass of nitrogen (N) is approximately 14.01 g/mol.
The atomic mass of oxygen (O) is approximately 16.00 g/mol.
Molar mass of N2O5 = (2 * 14.01 g/mol) + (5 * 16.00 g/mol)
Molar mass of N2O5 = 46.01 g/mol
Step 2: Calculate the number of moles of N2O5:
We can use the formula:
moles = mass / molar mass
moles of N2O5 = 32.4 g / 46.01 g/mol
moles of N2O5 ≈ 0.705 mol
Step 3: Determine the number of moles of oxygen (O):
The N2O5 molecule contains five oxygen atoms (O2) in total. So, the molar ratio of O to N2O5 is 5:1.
moles of O = moles of N2O5 * (5 moles of O / 1 mole of N2O5)
moles of O = 0.705 mol * 5
moles of O ≈ 3.525 mol
Therefore, there are approximately 3.525 moles of O in 32.4g of N2O5.
Step 4: Calculate the number of oxygen atoms present:
We can use Avogadro's number, which is approximately 6.022 x 10^23 atoms/mol, to convert moles to atoms.
number of oxygen atoms = moles of O * Avogadro's number
number of oxygen atoms ≈ 3.525 mol * 6.022 x 10^23 atoms/mol
The above calculation gives you the approximate number of oxygen atoms in 32.4g of N2O5.
Similarly, you can calculate the number of nitrogen atoms by multiplying the moles of N2O5 by the molar ratio of nitrogen (N) to N2O5, which is 2:1.
Please note that these calculations assume an ideal scenario and the values used are approximate atomic masses and Avogadro's number.