a string is wrapped around a cylinder with radius of 20cm. If the force of 300N is applied to the string, what is the magnitude of the torque that is developed about the axis?
300 N x 0.20 m = 60 Newton-meters
To find the magnitude of the torque developed about the axis, we need to use the formula:
Torque = Force × Radius × sin(θ)
First, we need to calculate the angle (θ) between the force and the radius. In this case, the force is being applied tangentially to the cylinder, so the angle between the force and the radius is 90 degrees or π/2 radians.
Next, let's calculate the torque using the given values:
Force = 300 N
Radius = 20 cm = 0.2 m
θ = π/2 radians
Now we can substitute the values into the formula:
Torque = 300 N × 0.2 m × sin(π/2)
sin(π/2) = 1, so the equation simplifies to:
Torque = 300 N × 0.2 m × 1
Finally, we can calculate the torque:
Torque = 300 N × 0.2 m
= 60 N·m
Therefore, the magnitude of the torque developed about the axis is 60 N·m.