Convert:
4600 bushel corn at standard moisture to ___tons
What does standard moisture mean?
Convert:
10 psfito ___ oz/in^2
To convert 4600 bushels of corn at standard moisture to tons, we first need to understand what "standard moisture" means. Standard moisture in the context of corn typically refers to the moisture content that is considered ideal or standard. It is often expressed as a percentage. Corn at standard moisture is usually around 15% moisture.
Now, let's proceed with the conversion:
1. Convert bushels to pounds:
To convert bushels of corn to pounds, we need to know the conversion factor. The conversion factor varies based on the crop, but for corn, the standard conversion is that 1 bushel of corn weighs approximately 56 pounds.
4600 bushels * 56 pounds/bushel = 257,600 pounds
2. Convert pounds to tons:
To convert pounds to tons, we divide the weight in pounds by 2,000 (since there are 2,000 pounds in a ton).
257,600 pounds / 2,000 = 128.8 tons
Therefore, 4600 bushels of corn at standard moisture is equal to 128.8 tons.
Regarding the second question:
To convert 10 psf (pounds per square foot) to oz/in^2 (ounces per square inch), we need to use the conversion factor:
1 lb/ft^2 = 0.0073 oz/in^2
So, to convert 10 psf to oz/in^2, we can use the following steps:
1. Convert psf to lb/ft^2:
Multiply the psf value by the conversion factor to get the value in lb/ft^2.
10 psf * 0.0073 lb/ft^2 = 0.073 lb/ft^2
2. Convert lb/ft^2 to oz/in^2:
To convert lb/ft^2 to oz/in^2, we need to multiply the lb/ft^2 value by 12 (to convert from feet to inches) and by 16 (to convert from pounds to ounces).
0.073 lb/ft^2 * 12 in/ft * 16 oz/lb = 14.016 oz/in^2
Therefore, 10 psf is equal to approximately 14.016 oz/in^2.