Find the Electron DOMAIN GEOMETRY & the MOLECULAR GEOMETRY of the following compounds:
1) ICl3
2) PCl3
3) XeF4
4) SF6
5) TeCl4
You must draw these out for yourself. We can't do these on this board. For ICl3, there are 5 domains which means electronic geometry of trigonal bipyramidal. Molecular geometry is T-shaped.
Here is a link. I expect you can find all of them through google. You can post here if you like and we can check your answers.
http://chemistry.about.com/od/workedchemistryproblems/a/How-To-Draw-A-Lewis-Structure-Octet-Exception.htm
To find the electron domain geometry and molecular geometry of the given compounds, we need to follow a few steps:
Step 1: Count the total number of valence electrons in the molecule.
Step 2: Determine the central atom by identifying the atom that forms the most bonds with other atoms.
Step 3: Assign the remaining electrons to the outer atoms, aiming for octet or duet (in the case of hydrogen).
Step 4: Calculate the number of electron domains around the central atom.
Step 5: Determine the electron domain geometry based on the number of electron domains.
Step 6: Determine the molecular geometry by considering the arrangement of atoms and any lone pairs.
1) ICl3:
- Iodine (I) is the central atom.
- Iodine has 7 valence electrons, and each chlorine (Cl) has 7 valence electrons. So, a total of 7 + (3 × 7) = 28 valence electrons.
- Iodine wants to form three bonds to achieve an octet. Therefore, each chlorine will be bonded to iodine.
- Iodine has three electron domains.
- The electron domain geometry is trigonal bipyramidal since there are three bonding domains and two lone pairs.
- The molecular geometry is T-shaped since there are three Cl atoms and two lone pairs around the central iodine atom.
2) PCl3:
- Phosphorus (P) is the central atom.
- Phosphorus has 5 valence electrons, and each chlorine (Cl) has 7 valence electrons. So, a total of 5 + (3 × 7) = 26 valence electrons.
- Phosphorus wants to form three bonds to achieve an octet. Therefore, each chlorine will be bonded to phosphorus.
- Phosphorus has four electron domains (three bonding and one lone pair).
- The electron domain geometry is tetrahedral since there are three bonding domains and one lone pair.
- The molecular geometry is pyramidal since there are three Cl atoms and one lone pair around the central phosphorus atom.
3) XeF4:
- Xenon (Xe) is the central atom.
- Xenon has 8 valence electrons, and each fluorine (F) has 7 valence electrons. So, a total of 8 + (4 × 7) = 36 valence electrons.
- Xenon wants to form four bonds to achieve an octet. Therefore, each fluorine will be bonded to xenon.
- Xenon has six electron domains (four bonding and two lone pairs).
- The electron domain geometry is octahedral since there are four bonding domains and two lone pairs.
- The molecular geometry is square planar since there are four F atoms and two lone pairs around the central xenon atom.
4) SF6:
- Sulfur (S) is the central atom.
- Sulfur has 6 valence electrons, and each fluorine (F) has 7 valence electrons. So, a total of 6 + (6 × 7) = 48 valence electrons.
- Sulfur wants to form six bonds to achieve an octet. Therefore, each fluorine will be bonded to sulfur.
- Sulfur has six electron domains (six bonding and no lone pairs).
- The electron domain geometry is octahedral since there are six bonding domains.
- The molecular geometry is also octahedral since there are six F atoms around the central sulfur atom.
5) TeCl4:
- Tellurium (Te) is the central atom.
- Tellurium has 6 valence electrons, and each chlorine (Cl) has 7 valence electrons. So, a total of 6 + (4 × 7) = 34 valence electrons.
- Tellurium wants to form four bonds to achieve an octet. Therefore, each chlorine will be bonded to tellurium.
- Tellurium has five electron domains (four bonding and one lone pair).
- The electron domain geometry is trigonal bipyramidal since there are four bonding domains and one lone pair.
- The molecular geometry is seesaw since there are four Cl atoms and one lone pair around the central tellurium atom.
By following these steps and considering the valence electrons and bonding patterns, you can determine the electron domain geometry and molecular geometry of the given compounds.