Electron DOMAIN GEOMETRY & the MOLECULAR GEOMETRY of the following compounds:
1) ICl3
2) PCl3
3) XeF4
4) SF6
5) TeCl4
and what is your question?
How do you find it?
To determine the electron domain geometry and molecular geometry of a compound, we need to consider the number of electron domains and the presence of lone pairs on the central atom.
1) ICl3:
To determine the electron domain geometry of ICl3:
- Iodine (I) is the central atom and it has 7 valence electrons.
- Chlorine (Cl) has 7 valence electrons each.
- The total number of valence electrons is 2(7) + 3(7) = 35.
- Since there are no lone pairs, all 35 electrons are involved in bonding.
- ICl3 has 3 bonding domains and 0 lone pairs.
- Therefore, the electron domain geometry is trigonal planar.
To determine the molecular geometry of ICl3:
- We use the VSEPR theory, which states that electron domains (bonding and lone pairs) will arrange themselves to be as far apart as possible.
- The three bonding domains will arrange themselves in a trigonal planar shape.
- Since there are no lone pairs, the molecular geometry is also trigonal planar.
2) PCl3:
To determine the electron domain geometry of PCl3:
- Phosphorus (P) is the central atom and it has 5 valence electrons.
- Chlorine (Cl) has 7 valence electrons each.
- The total number of valence electrons is 5 + 3(7) = 26.
- Since there are no lone pairs, all 26 electrons are involved in bonding.
- PCl3 has 3 bonding domains and 0 lone pairs.
- Therefore, the electron domain geometry is trigonal planar.
To determine the molecular geometry of PCl3:
- Again, the three bonding domains will arrange themselves in a trigonal planar shape.
- Since there are no lone pairs, the molecular geometry is also trigonal planar.
3) XeF4:
To determine the electron domain geometry of XeF4:
- Xenon (Xe) is the central atom and it has 8 valence electrons.
- Fluorine (F) has 7 valence electrons each.
- The total number of valence electrons is 8 + 4(7) = 36.
- Since there are no lone pairs, all 36 electrons are involved in bonding.
- XeF4 has 4 bonding domains and 0 lone pairs.
- Therefore, the electron domain geometry is tetrahedral.
To determine the molecular geometry of XeF4:
- For a tetrahedral electron domain geometry, the molecular geometry depends on the presence of lone pairs.
- In XeF4, there are 4 bonding domains and no lone pairs.
- The molecular geometry will be the same as the electron domain geometry, which is tetrahedral.
4) SF6:
To determine the electron domain geometry of SF6:
- Sulfur (S) is the central atom and it has 6 valence electrons.
- Fluorine (F) has 7 valence electrons each.
- The total number of valence electrons is 6 + 6(7) = 48.
- Since there are no lone pairs, all 48 electrons are involved in bonding.
- SF6 has 6 bonding domains and 0 lone pairs.
- Therefore, the electron domain geometry is octahedral.
To determine the molecular geometry of SF6:
- For an octahedral electron domain geometry, the molecular geometry depends on the presence of lone pairs.
- In SF6, there are 6 bonding domains and no lone pairs.
- The molecular geometry will be the same as the electron domain geometry, which is octahedral.
5) TeCl4:
To determine the electron domain geometry of TeCl4:
- Tellurium (Te) is the central atom and it has 6 valence electrons.
- Chlorine (Cl) has 7 valence electrons each.
- The total number of valence electrons is 6 + 4(7) = 34.
- Since there are no lone pairs, all 34 electrons are involved in bonding.
- TeCl4 has 4 bonding domains and 0 lone pairs.
- Therefore, the electron domain geometry is tetrahedral.
To determine the molecular geometry of TeCl4:
- For a tetrahedral electron domain geometry, the molecular geometry depends on the presence of lone pairs.
- In TeCl4, there are 4 bonding domains and no lone pairs.
- The molecular geometry will be the same as the electron domain geometry, which is tetrahedral.
Remember that the molecular geometry is determined by the arrangement of atoms in a molecule, while the electron domain geometry includes both atoms and lone pairs around the central atom.