A Packaging Company sells soda and claims each can contains 12 oz. A random sample of 15 sodas yielded a sample mean of 11.2 oz. Given the sample standard deviation is 0.3 oz, estimate the margin of error for a 90% confidence interval.

To estimate the margin of error for a 90% confidence interval, you can use the formula:

Margin of Error = Critical value * (Standard deviation / √sample size)

In this case, you have a sample size of 15 sodas, a sample mean of 11.2 oz, and a sample standard deviation of 0.3 oz. You need to find the critical value for a 90% confidence interval.

To find the critical value, you can use a t-distribution table or statistical software. The critical value depends on the confidence level and the degrees of freedom. Since the sample size is 15, the degrees of freedom are 15 - 1 = 14.

Looking up the critical value for a 90% confidence level and 14 degrees of freedom using a t-distribution table, you would find it to be approximately 1.761.

Now that you have the critical value, you can substitute it along with the standard deviation and sample size into the formula:

Margin of Error = 1.761 * (0.3 / √15)

Calculating this expression will give you the estimated margin of error for a 90% confidence interval.