Toluene, C6H5CH3, is a liquid similar to benzene, C6H6. It is the starting material for other substances, including trinitrotoluene (TNT). the molality of toluene in a solution that contains 26.2 g of toluene and 132 g of benzene.
Calculate the molar fraction of toluene and benzene from the previous exercise. ?
n toluene = grams/molar mass
n benzene = grams/molar mass.
totl N = n toluene + n benzene
Xtolune = n toluene/total mols.
Xbenzene = n benzene/total mols.
To calculate the molar fraction of toluene and benzene, we need to first calculate the moles of each substance present in the solution.
Step 1: Calculate the moles of toluene (C6H5CH3)
Molar mass of toluene (C6H5CH3) = (12.01 g/mol + 6 * 1.008 g/mol + 6 * 12.01 g/mol) = 92.14 g/mol
Moles of toluene = mass of toluene / molar mass of toluene
= 26.2 g / 92.14 g/mol
≈ 0.284 mol
Step 2: Calculate the moles of benzene (C6H6)
Molar mass of benzene (C6H6) = (6 * 12.01 g/mol + 6 * 1.008 g/mol) = 78.11 g/mol
Moles of benzene = mass of benzene / molar mass of benzene
= 132 g / 78.11 g/mol
≈ 1.690 mol
Step 3: Calculate the total moles of the solution
Total moles of the solution = moles of toluene + moles of benzene
= 0.284 mol + 1.690 mol
≈ 1.974 mol
Step 4: Calculate the molar fraction of toluene
Molar fraction of toluene = moles of toluene / total moles of the solution
= 0.284 mol / 1.974 mol
≈ 0.144
Step 5: Calculate the molar fraction of benzene
Molar fraction of benzene = moles of benzene / total moles of the solution
= 1.690 mol / 1.974 mol
≈ 0.856
So, the molar fraction of toluene is approximately 0.144 and the molar fraction of benzene is approximately 0.856 in the given solution.