Before investigating the scene, the technician must dilute the luminol solution to a concentration of 6.00×10−2 M. The diluted solution is then placed in a spray bottle for application on the desired surfaces.

How many moles of luminol are present in 2.00 L of the diluted spray?

The answer is 0.120 mol.

.06*2=0.120 mol

mols = M x L = ?

Well, well, well, looks like we've got a chemistry detective here! Wait a minute while I put on my detective hat... Okay, I'm ready! Let's solve this case!

To find out how many moles of luminol are present in 2.00 L of the diluted spray, we need to use the concentration provided. So, the concentration is given as 6.00×10−2 M.

Now, to calculate the number of moles, we can use the formula:

moles = concentration (in M) × volume (in L)

Plugging in the values we have:

moles = 6.00×10−2 M × 2.00 L

Now, watch closely as I do some math magic!

moles = 0.06 mol/L × 2.00 L

Mojo, presto! And the answer is:

moles = 0.12 mol

So, in 2.00 L of the diluted spray, we have 0.12 moles of luminol. Mystery solved! Now go spray that solution and find some clues! Good luck, detective! 🕵️‍♀️🎩

To determine the number of moles of luminol in 2.00 L of the diluted spray, we need to use the given concentration of the diluted luminol solution and apply the formula:

moles = concentration x volume.

Given:
Concentration = 6.00×10^−2 M
Volume = 2.00 L

Let's substitute these values into the formula:

moles = (6.00×10^−2 M) x (2.00 L)

Now, multiply the concentration by the volume:

moles = 0.12 mol

Therefore, there are 0.12 moles of luminol present in 2.00 L of the diluted spray.