you drop a penny off the roof and it htis the water 4.2 seconds later, what is the height of the bridge?
Y = (g/2)*t^2 is the distance it falls in time t, neglecting air restance.
g = 9.8 m/s^2 is the acceleration of gravity.
I don't quite see how a roof, a bridge and the water below are related. Is the roof higher than the bridge?
To find the height of the bridge, we can use the equation of motion for an object in freefall:
h = 1/2 * g * t^2
Where:
h is the height of the bridge,
g is the acceleration due to gravity (which is approximately 9.8 m/s^2 on Earth),
t is the time it takes for the object to fall (given as 4.2 seconds in this case).
Now, let's plug in the values into the equation:
h = 1/2 * (9.8 m/s^2) * (4.2 s)^2
Simplifying the equation:
h = 1/2 * 9.8 * 17.64
h = 88.2 meters
Therefore, the height of the bridge is approximately 88.2 meters.