How many moles of oxygen molecules would be produced from the decomposition of 25moles of potassium trioxochlorate (v) ?
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To determine the number of moles of oxygen molecules produced from the decomposition of potassium trioxochlorate (V), we first need to understand the chemical equation for the decomposition reaction.
The chemical formula for potassium trioxochlorate (V) is KClO₃. When it decomposes, it yields potassium chloride (KCl) and oxygen gas (O₂):
2KClO₃ → 2KCl + 3O₂
From the balanced chemical equation, we can see that 2 moles of potassium trioxochlorate (V) produce 3 moles of oxygen gas.
To calculate the number of moles of oxygen gas produced from 25 moles of potassium trioxochlorate (V), we can set up a simple proportion:
2 moles KClO₃ / 3 moles O₂ = 25 moles KClO₃ / x moles O₂
Cross-multiplying, we get:
2 * x = 3 * 25
Simplifying:
2x = 75
Dividing both sides by 2:
x = 37.5
Therefore, the decomposition of 25 moles of potassium trioxochlorate (V) would produce 37.5 moles of oxygen molecules. However, since moles cannot be expressed using decimal points, we round the value down to the nearest whole number. Thus, approximately 37 moles of oxygen molecules would be produced.