Animals break down glucose (C6H12O6) as a source of energy according to the following overall reaction.

C6H12O6(aq) + 6O2(g) �¨ 6CO2(g) + 6H2O(l)
What mass in grams of CO2(g) is produced from the reaction of 15.0 g of glucose?

21.98 grams

convert the 15g glucose to moles of glucose. You get 6 times that number of moles of CO2. Convert that then to grams.

Well, if you have 15.0 g of glucose and you're asking about CO2 production, it sounds like you're trying to balance your diet. Glucose, also known as sugar, is delicious but not too healthy in large quantities. So, let's see how much CO2 you'll be emitting after a sugary treat!

According to the balanced equation, 1 mol of glucose produces 6 mol of CO2. To find the molar mass, we need to know the molar mass of glucose, which is 180.18 g/mol.

So, first, we need to find the number of moles of glucose in 15.0 g. By dividing the mass by the molar mass, we get:

moles of glucose = 15.0 g / 180.18 g/mol

Now, since we know that the ratio is 1:6, we multiply the number of moles of glucose by 6 to get the number of moles of CO2:

moles of CO2 = moles of glucose × 6

Finally, to find the mass of CO2, we multiply the number of moles of CO2 by the molar mass of CO2, which is 44.01 g/mol:

mass of CO2 = moles of CO2 × 44.01 g/mol

And there you have it! The mass of CO2 produced from 15.0 g of glucose. But remember, I hope you're not planning on inhaling or exhaling CO2 as a diet plan!

To determine the mass of CO2 produced from the reaction of 15.0 g of glucose, we need to use stoichiometry.

From the balanced equation, we can see that 1 mole of glucose (C6H12O6) produces 6 moles of CO2.

Step 1: Convert the mass of glucose to moles using the molar mass of glucose.
The molar mass of glucose (C6H12O6) is:
(6 * 12.01 g/mol) + (12 * 1.01 g/mol) + (6 * 16.00 g/mol) = 180.18 g/mol

15.0 g of glucose is equivalent to:
15.0 g / 180.18 g/mol = 0.083 moles of glucose

Step 2: Use the mole ratio to find moles of CO2 produced.
From the balanced equation, we know that 1 mole of glucose produces 6 moles of CO2.

Therefore, 0.083 moles of glucose will produce:
0.083 moles * 6 moles CO2/mol glucose = 0.498 moles of CO2

Step 3: Convert moles of CO2 to grams using the molar mass of CO2.
The molar mass of CO2 is:
(1 * 12.01 g/mol) + (2 * 16.00 g/mol) = 44.01 g/mol

Therefore, 0.498 moles of CO2 is equivalent to:
0.498 moles * 44.01 g/mol = 21.96 g of CO2

Therefore, 15.0 g of glucose will produce 21.96 g of CO2.

To find the mass of CO2 produced from the reaction of 15.0 g of glucose, we need to use stoichiometry.

Step 1: Determine the molar mass of glucose (C6H12O6):
The molar mass of carbon (C) is 12.01 g/mol, hydrogen (H) is 1.01 g/mol, and oxygen (O) is 16.00 g/mol. To find the molar mass of glucose, we add up the molar masses of all its atoms:
(6×C) + (12×H) + (6×O) = (6×12.01) + (12×1.01) + (6×16.00) = 72.06 + 12.12 + 96.00 = 180.18 g/mol.

Step 2: Write the balanced chemical equation:
C6H12O6(aq) + 6O2(g) → 6CO2(g) + 6H2O(l)

From the balanced equation, we see that 1 mole of glucose reacts to produce 6 moles of CO2 (and 6 moles of water).

Step 3: Convert grams of glucose to moles:
Given that the mass of glucose is 15.0 g, we can use its molar mass (180.18 g/mol) to convert grams to moles:
15.0 g glucose × (1 mol/180.18 g) = 0.0833 mol glucose (rounded to 4 decimal places).

Step 4: Use stoichiometry to find moles of CO2:
From the balanced equation, we know that 1 mole of glucose produces 6 moles of CO2. Therefore, we can set up a proportion:
0.0833 mol glucose × (6 mol CO2/1 mol glucose) = 0.4998 mol CO2 (rounded to 4 decimal places).

Step 5: Convert moles of CO2 to grams:
Finally, use the molar mass of CO2 (44.01 g/mol) to convert moles of CO2 to grams:
0.4998 mol CO2 × (44.01g/1 mol) = 21.99 g CO2 (rounded to 2 decimal places).

Therefore, the mass of CO2 produced from the reaction of 15.0 g of glucose is approximately 21.99 grams.