Consider the reaction at equilibrium:
CaO(s) + CO2(g) ! CaCO3(s)
If you add more CaO to the system, how will the system respond?
"!" Do you mean ->? No change because you are adding more solid to an equilibrium.
i believe that was supposed to be an arrow
ok then no change.
To predict how the system will respond when more CaO is added, we need to understand the Le Chatelier's principle. According to this principle, when a system at equilibrium is subjected to a change in conditions, it will respond in a way that tends to counteract the change and restore equilibrium.
In this reaction, CaO and CO2 react to form CaCO3. If more CaO is added to the system, the reaction will initially be shifted to the right to utilize the excess CaO. This is because the system will try to decrease the concentration of CaO to reestablish equilibrium.
By consuming the additional CaO, more CaCO3 will be formed until a new equilibrium is reached. This is because the product, CaCO3, is decreasing due to the increased concentration of CaO being converted.
Overall, adding more CaO will shift the reaction to the right, resulting in an increase in the concentration of CaCO3 and a decrease in the concentration of CO2.