energy required to raise the temp of H2O from -15C to 125c
To calculate the energy required to raise the temperature of H2O (water) from -15°C to 125°C, we can use the formula:
Q = m * c * ΔT
Where:
Q is the energy (in joules),
m is the mass of water (in grams),
c is the specific heat capacity of water (which is 4.18 J/g°C),
ΔT is the change in temperature (in °C).
First, we need to convert the given temperatures from Celsius to Kelvin, as temperature in Kelvin is required for calculations.
T1 = -15°C + 273.15 = 258.15 K
T2 = 125°C + 273.15 = 398.15 K
Now, we can calculate the change in temperature (ΔT):
ΔT = T2 - T1
= 398.15 K - 258.15 K
= 140 K
Next, we need the mass of water. Let's assume a value of 100 grams.
Now, we can substitute the values into the formula:
Q = m * c * ΔT
= 100 g * 4.18 J/g°C * 140 K
= 584,800 J
Therefore, the energy required to raise the temperature of 100 grams of water from -15°C to 125°C is 584,800 joules.