in order to dilute 40.0 ml of .600 m hcl to .100 m, the volume of water that would need to be added would be?
To determine the volume of water needed to dilute a solution, you can use the dilution formula:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution (in this case, 0.600 M HCl)
V1 = initial volume of the solution (in this case, 40.0 mL)
C2 = final concentration of the solution (in this case, 0.100 M HCl)
V2 = final volume of the solution
Now, let's rearrange the formula to solve for V2 (volume of water):
V2 = (C1V1) / C2
Plugging in the values:
V2 = (0.600 M)(40.0 mL) / 0.100 M
V2 = 240 mL
Therefore, you would need to add 240 mL of water to the 40.0 mL of 0.600 M HCl in order to obtain a final concentration of 0.100 M.