how many phosphorus atoms are present in 25.0 g of P4O10 ?
P.o. 2
To determine the number of phosphorus atoms in 25.0 g of P4O10, we need to follow these steps:
Step 1: Find the molar mass of P4O10.
The molar mass of P4O10 is the sum of the molar masses of phosphorus (P) and oxygen (O):
(4 * atomic mass of P) + (10 * atomic mass of O)
Step 2: Convert the given mass from grams to moles.
To convert grams to moles, we need to divide the given mass by the molar mass of P4O10:
moles = mass / molar mass
Step 3: Determine the number of moles of phosphorus (P) in P4O10.
Since there are 4 phosphorus atoms in P4O10, the number of moles of P is 4 times the moles of P4O10.
Step 4: Calculate the number of phosphorus atoms.
The number of phosphorus atoms can be found by multiplying the number of moles of P by Avogadro's number (6.022 x 10^23 atoms/mol).
Let's calculate the number of phosphorus atoms:
Step 1: Calculate the molar mass of P4O10:
(4 * atomic mass of P) + (10 * atomic mass of O)
= (4 * 30.97 g/mol) + (10 * 16.00 g/mol)
= 123.88 g/mol + 160.00 g/mol
= 283.88 g/mol
Step 2: Convert the given mass to moles:
moles = 25.0 g / 283.88 g/mol
moles ≈ 0.088 mol
Step 3: Determine the number of moles of P:
4 * 0.088 mol
= 0.352 mol
Step 4: Calculate the number of phosphorus atoms:
Number of phosphorus atoms = 0.352 mol * 6.022 x 10^23 atoms/mol
Number of phosphorus atoms ≈ 2.12 x 10^23
Therefore, there are approximately 2.12 x 10^23 phosphorus atoms in 25.0 g of P4O10.
To determine the number of phosphorus atoms present in 25.0 g of P4O10, you need to follow these steps:
1. Find the molar mass of P4O10:
- P: 30.97 g/mol (phosphorus atomic mass)
- O: 16.00 g/mol (oxygen atomic mass)
- P4O10 consists of 4 phosphorus atoms and 10 oxygen atoms.
- Molar mass of P4O10 = (4 * 30.97 g/mol) + (10 * 16.00 g/mol) = 283.88 g/mol
2. Calculate the number of moles:
- Moles = Mass / Molar mass
- Moles = 25.0 g / 283.88 g/mol ≈ 0.088 moles
3. Use Avogadro's number:
- Avogadro's number = 6.022 × 10^23 atoms/mole
- Number of phosphorus atoms = Moles * Avogadro's number
- Number of phosphorus atoms = 0.088 moles * 6.022 × 10^23 atoms/mole
Therefore, in 25.0 g of P4O10, there are approximately 5.293 × 10^22 phosphorus atoms.
mols P4O10 = grams/molar mass
mols P atoms are 4x that.