# Chemistry

What mass of solution containing 6.50% sodium sulfate N2SO4 by mass contains 1.50g Na2SO4

Set up a proportion.
(g Na2SO4/g solution) = (1.50 g Na2SO4/x g solution).
Solve for x. Check my work.

how do you fine g solution

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1. 6.5 g Na2SO4 per 100 g solution.
6.5 goes on top, 100 goes on bottom.

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2. so for this part
(g Na2SO4/g solution) = (1.50 g Na2SO4/x g solution).
it would be (g Na2SO4/ .065 g solution = 1.50 g Na2SO4/ x .065 g solution ) or did i miss place them

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3. No.
It would be (6.5/100) = (1.50/x g solution)

Then cross multiply to obtain,
6.5*x = 100*1.5
x = ??

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4. 23.0769 right

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5. The digits are right. I would round it to 23 since you have only two significant digits in the 6.5%. But 23 what? grams. mL. ounces. pounds.

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