How many mL of 5.5 M KOH are needed to prepare 300 mL of 0.2 M KOH?
The dilution formula is
c1v1 = c2v2
To calculate the volume of a concentrated solution needed to prepare a diluted solution, you can use the following formula:
C₁V₁ = C₂V₂
Where:
C₁ = initial concentration of the solution (in this case, the concentrated KOH solution) in units of moles per liter (M)
V₁ = volume of the concentrated solution needed (what we need to find)
C₂ = final concentration of the solution (in this case, the diluted KOH solution) in units of moles per liter (M)
V₂ = final volume of the diluted solution (in this case, 300 mL)
Let's plug in the given values into the formula:
(5.5 M) x (V₁ mL) = (0.2 M) x (300 mL)
To solve for V₁, we need to rearrange the equation:
V₁ = (0.2 M x 300 mL) / 5.5 M
Now, let's calculate:
V₁ = (0.2 x 300) / 5.5
V₁ = 10.909 mL
Therefore, approximately 10.909 mL of the 5.5 M KOH solution is needed to prepare 300 mL of 0.2 M KOH solution.