What would the coefficient be for the produced salt in a balanced chemical equation of this acid and base?
HNO3 + Ca(OH)2 -->Ca(NO3)2 + H2O
What would the coefficient be for the produced salt in a balanced chemical equation of this acid and base?
H2SO4 + KOH -->K2SO4 + H2O
See your post above.
To determine the coefficient for the produced salt in a balanced chemical equation, we need to first balance the equation. Let's go through the steps for each of the given equations:
1. HNO3 + Ca(OH)2 → Ca(NO3)2 + H2O
To balance this equation, we need to make sure that the number of atoms on each side of the equation is the same.
Start by counting the number of each type of atom on each side:
- Left side: H: 1, N: 1, O: 3, Ca: 1
- Right side: Ca: 1, N: 2, O: 6, H: 2
To balance the hydrogen atoms, we need to add a coefficient of 2 in front of HNO3:
2HNO3 + Ca(OH)2 → Ca(NO3)2 + H2O
Now let's count the number of each type of atom again:
- Left side: H: 2, N: 2, O: 6, Ca: 1
- Right side: Ca: 1, N: 2, O: 6, H: 2
We can see that the equation is now balanced. The coefficient for the produced salt, Ca(NO3)2, is 1.
2. H2SO4 + KOH → K2SO4 + H2O
Following the same steps as before, let's count the number of each type of atom on each side of the equation:
- Left side: H: 2, S: 1, O: 4, K: 1
- Right side: K: 2, S: 1, O: 4, H: 2
To balance the hydrogen atoms, we need to add a coefficient of 2 in front of H2SO4:
2H2SO4 + KOH → K2SO4 + H2O
Now let's count the number of each type of atom again:
- Left side: H: 4, S: 2, O: 8, K: 1
- Right side: K: 2, S: 1, O: 4, H: 2
We can see that the equation is now balanced. The coefficient for the produced salt, K2SO4, is 1.
Therefore, in both equations, the coefficient for the produced salt is 1.