cosx/sinxcotx=1
LS = cotx cotx
= cot^2 x
≠ RS
This is not an identity the way you typed it
if you meant
cosx/(sinxcotx) = 1
LS = cosx/(sinxcosx/sinx)
= cosx/cosx
= 1
= RS
See how important it is to use brackets when typing in this way ?
I apologize 4 the typo, that's how the work was given to me.
But thanks alot!
To solve the equation cos(x)/sin(x) * cot(x) = 1, we can simplify the left side of the equation by applying basic trigonometric identities.
First, let's simplify cos(x)/sin(x):
Using the identity cos(x)/sin(x) = cot(x), we can rewrite the equation as cot(x) * cot(x) = 1.
Now, we have cot(x)^2 = 1. To solve for cot(x), we can take the square root of both sides:
√(cot(x)^2) = √1
This simplifies to |cot(x)| = 1.
Now, we have two possibilities to consider:
1. cot(x) = 1
2. cot(x) = -1
To find the values of x, we can take the inverse cotangent (or arccotangent) of both sides for each case:
1. cot(x) = 1 => x = arccot(1) = π/4 + πn (where n is an integer)
2. cot(x) = -1 => x = arccot(-1) = 3π/4 + πn (where n is an integer)
So, the solutions for the equation cos(x)/sin(x) * cot(x) = 1 are x = π/4 + πn and x = 3π/4 + πn, where n is an integer.