if the ratio of free throws made to free throws attempted is 5 to 6 what would be the possible number of free throws made and free throws attempted
5/6 = 10/12 = 15/18 = 20/24
You get the idea --
This did not help me at all this got me a d and know I have a bad grade in my math class thanks a lot and she sai if we needed a site we could use it to see if our Anwar is right ugh.
To find the possible number of free throws made and attempted, we can set up a proportion based on the given ratio.
The ratio of free throws made to free throws attempted is 5 to 6.
Let's let the number of free throws made be represented by x, and the number of free throws attempted be represented by y.
Therefore, we can set up the following proportion:
5/6 = x/y
To solve for x and y, we cross-multiply:
5y = 6x
Now, we can find the possible values of x and y by selecting a value for one variable and solving for the other. Let's choose a number for y, such as y = 12.
If y equals 12, then the equation becomes:
5(12) = 6x
60 = 6x
Dividing both sides by 6, we get:
x = 10
Therefore, when free throws attempted (y) is 12, the possible values for free throws made (x) could be 10.
You can repeat this process with different values for y to find other possible combinations of free throws made and attempted that satisfy the given ratio.