What volume of a 3M KOH solution can be prepared by diluting 0.5L of a 5M KOH solution?
3M KOH x ?L KOH = 5M KOH x 0.5L KOH.
Solve for ?L KOH.
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To find out what volume of a 3M KOH solution can be prepared by diluting 0.5L of a 5M KOH solution, we can use the dilution equation:
C₁V₁ = C₂V₂
where:
C₁ = initial concentration of the solution (5M)
V₁ = initial volume of the solution (0.5L)
C₂ = final concentration of the solution (3M)
V₂ = final volume of the solution (unknown)
Rearranging the equation, we can solve for V₂:
V₂ = (C₁V₁) / C₂
Substituting the given values:
V₂ = (5M * 0.5L) / 3M
V₂ = 2.5L / 3M
To get the volume in liters, we divide 2.5L by 3:
V₂ = 0.8333... L
Therefore, approximately 0.8333 liters (or 833.3 mL) of a 3M KOH solution can be prepared by diluting 0.5L of a 5M KOH solution.