What volume of a 3M KOH solution can be prepared by diluting 0.5L of a 5M KOH solution?

3M KOH x ?L KOH = 5M KOH x 0.5L KOH.

Solve for ?L KOH.

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To find out what volume of a 3M KOH solution can be prepared by diluting 0.5L of a 5M KOH solution, we can use the dilution equation:

C₁V₁ = C₂V₂

where:
C₁ = initial concentration of the solution (5M)
V₁ = initial volume of the solution (0.5L)
C₂ = final concentration of the solution (3M)
V₂ = final volume of the solution (unknown)

Rearranging the equation, we can solve for V₂:

V₂ = (C₁V₁) / C₂

Substituting the given values:

V₂ = (5M * 0.5L) / 3M

V₂ = 2.5L / 3M

To get the volume in liters, we divide 2.5L by 3:

V₂ = 0.8333... L

Therefore, approximately 0.8333 liters (or 833.3 mL) of a 3M KOH solution can be prepared by diluting 0.5L of a 5M KOH solution.