A camera flashtube requires 5.0J of energy per flash. The flash duration is 1.0 ms. (a) what power does the flashtube use while it's flashing? (b)If the flashtube operates at 200V, what capacitance is needed to supply the flash energy? (c) If the flashtube is fired once every 10s, what's the average power consumption?
(a) power = (discharge energy)/duration
= 5000 W
(b) discharge energy = (1/2)*C*V^2
Solve for C
(c) Avg. Power
= (Energy per flash)*(0.1 flashes/sec)
To answer these questions, we can use the equations related to power, energy, voltage, and capacitance.
(a) To calculate the power used by the flashtube, we can use the formula:
Power = Energy / Time
Given that the energy required per flash is 5.0J and the flash duration is 1.0 ms (or 0.001s), we can substitute these values into the equation:
Power = 5.0J / 0.001s = 5000W
Therefore, the flashtube uses 5000W (or 5 kilowatts) of power while it's flashing.
(b) To calculate the capacitance needed to supply the flash energy, we can use the formula:
Energy = 0.5 * Capacitance * Voltage^2
Given that the energy required per flash is 5.0J and the voltage is 200V, we can rearrange the equation to solve for capacitance:
Capacitance = (2 * Energy) / (Voltage^2)
Capacitance = (2 * 5.0J) / (200V)^2 = 0.000125F
Therefore, the capacitance needed to supply the flash energy is 0.000125F (or 125 microfarads).
(c) To calculate the average power consumption when the flashtube is fired once every 10s, we need to find the energy consumed per second and then calculate the power.
Since the flashtube is fired once every 10s, the energy consumed per second can be calculated by dividing the energy per flash (5.0J) by the time interval (10s):
Energy per second = 5.0J / 10s = 0.5J/s
Now we can calculate the average power consumption using the formula:
Average Power = Energy per second / Time
Average Power = 0.5J/s / 10s = 0.05W
Therefore, the average power consumption is 0.05W (or 50 milliwatts).
(a) To find the power, we can use the formula:
Power (P) = Energy (E) / Time (t)
Given that the energy per flash (E) is 5.0 J and the flash duration (t) is 1.0 ms (or 0.001 s), we can substitute these values into the formula:
P = 5.0 J / 0.001 s
P = 5000 W
Therefore, the power used by the flashtube while it's flashing is 5000 W.
(b) To find the capacitance needed to supply the flash energy, we can use the formula:
Energy (E) = (1/2) * Capacitance (C) * Voltage^2
Given that the energy per flash (E) is 5.0 J and the voltage (V) is 200V, we can rearrange the formula to solve for the capacitance (C):
C = (2 * E) / V^2
Substituting the given values:
C = (2 * 5.0 J) / (200V)^2
C = 0.000125 F
Therefore, a capacitance of 0.000125 F is needed to supply the flash energy.
(c) To find the average power consumption when the flashtube is fired once every 10s, we can use the formula:
Average Power (P) = Energy (E) / Time (t)
Given that the energy per flash (E) is 5.0 J and the time interval between flashes (t) is 10s, we can substitute these values into the formula:
P = 5.0 J / 10s
P = 0.5 W
Therefore, the average power consumption is 0.5 W when the flashtube is fired once every 10s.