The number of moles of hydrogen gas present in a 1500 mL container at 298 K and 2.0 atm pressure is?
Use PV = nRT, solve for n = number of moles. Don't forget T must be in kelvin.
0.12 moles
To calculate the number of moles of hydrogen gas, we can use the ideal gas equation:
PV = nRT
Where:
P = pressure in atm
V = volume in liters
n = number of moles
R = ideal gas constant (0.0821 L⋅atm/mol⋅K)
T = temperature in Kelvin
First, let's convert the volume from milliliters to liters:
1500 mL = 1500/1000 = 1.5 L
Now we can substitute the values into the ideal gas equation:
2.0 atm * 1.5 L = n * 0.0821 L⋅atm/mol⋅K * 298 K
Simplifying the equation:
3.0 atm⋅L = n * 24.4438 L⋅atm/mol
Now we can solve for n (number of moles):
n = 3.0 atm⋅L / 24.4438 L⋅atm/mol
n ≈ 0.1227 mol
Therefore, the number of moles of hydrogen gas present in the 1500 mL container at 298 K and 2.0 atm pressure is approximately 0.1227 mol.
To determine the number of moles of hydrogen gas present in the given container, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature (in Kelvin)
First, let's convert the given volume from mL to liters:
1500 mL = 1500 mL x (1 L / 1000 mL) = 1.5 L
Now we can substitute the given values into the ideal gas law equation to solve for the number of moles:
(2.0 atm) x (1.5 L) = n x (0.0821 L·atm/mol·K) x (298 K)
Simplifying the equation, we have:
3.0 = n x (24.4438)
Divide both sides of the equation by 24.4438 to solve for n:
n = 3.0 / 24.4438
Calculating the value gives:
n ≈ 0.1228 mol
Therefore, the number of moles of hydrogen gas present in the 1500 mL container at 298 K and 2.0 atm pressure is approximately 0.1228 mol.